Question

And this one? y=3^{x^3-2x --> y'?

Answer 1

y'?\[ y=3^{x^3-2x} --> y'?\]

Answer 2

\[y=3^u y'=u(3^{u-1})*u'\] correct?

Answer 3

Take the log of both sides, use the power rule on the right side, and differentiate implicitly.

Answer 4

by using the formula a^x=a^xlna
(3x^2-2)3^(x^3-2x).ln3