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how to find exact value of cos(Arcsin(5/13))
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Draw a right triangle. Label a side 5 Label the hypotenuse 13. You should see it from that drawing.
cos= opposite over the hypotenuse
@Valerieeeee_8412 No, that would be the sine.
thats right, i meant adjacent over hypotenuse
Good call. But we must first designate an angle opposite the '5' and then calculate the length of the adjacent side.
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Hint: \(\cos(\arcsin(x))=\sqrt{1-x^2}\).
thanks i used the triangle method. but ill just talk it over with my trig teacher tomorrow
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