Question

find the distance between p1 and p2

p1= (-4,5) ; p2= (5,1)

Answer 1

distance is sqrt(x2-x1)^2+(y2-y1)^2

Answer 2

Gawsh that was supposed to be a + instead of a - -_- lol \[\large d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}\]\[\large (x_{1},y_{1}) \implies (-4,5)\]\[\large (x_{2},y_{2}) \implies (5,1)\]