Question

what is the fourth term of (x-2)^8

Answer 1

Do you know the formula for getting a term in binomial expansion?

Answer 2

use pascal's triangle.

Answer 3

No need to do that mack.

Answer 4

Here is the formula to find the (n+1)th term of expression : \((x+y)^a\)

\(\large T_{n+1} = ^a C _ n x^{n-a} y^a \) \

Here we are given with the expression : \((x-2)^8\) , that is a = 8

\(\large T_{4} = T_{3+1} = ^8 C _ 3 x^{8-3} (-2)^3 \)

[ By : \(T_n \) I meant, nth term. ]

Answer 5

Solving it further, you will get the 4th term of the expansion : \((x-2)^8\)