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The cost of three notebooks and four pencils is $8.50. The cost of five notebooks and eight pencils is $14.5". Determine the cost of one notebook and the cost of one pencil. (Needs an algebraic solution)
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$14.50*
lets call x notebooks and y pencils
\[3N +4P = 8.50\]\[5N + 8P = 14.50\]Multiply the top equation by -2. \[-6N - 8P = -17\] use elimination to solve. -6N-8P = -17 5N +8P = 14.50 Result: -N = -2.50 N(otebook) = 2.50 Plug in N to either equation. 3(2.50) +4p = 8.50 4P + 7.5 = 8.50 4P = 1 P = .25
Okay
the first equation will then look like 3x + 4y =$8.50
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