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Write an exponential function y=ab^x for a graph that will include that will include (0,4) and (2, 49).
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I am not sure how to write equations, and I could really use the help on this.
\(ab^0 = ?\)
\[ \begin{cases} ab^0 = a & \\ ab^0 = 4 &\text{ as asked} \end{cases} \] therefore \(a=4\). Now you can find \(b\).
4=a b^0 b^0 =1 a=4 49 = 4 b^2 b = (1/2)log(49/4)
Principle log(x^n) = n log(x)
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