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solving logarithmic and exponential equations 1. 8-3^x = -1 2. log(lowered 3)81=x 3. log x- log3=3
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8-3^x = -1 3^x =9 x log(3) =9 x=9/log(3) log x- log3=3 log(x) = 3 + log(3) x = 10^(log(3)+3) x= ]10^log(3)] 10^3 x=3 10^3
are those the answers to 1 and 3?
Does it look like the solutions
Well I got 3 as the solution on number 1... 2.587 for number 7 and 300 for number 3?? are those right?
I didn't do pb 2 because I didn't know what lowered 3 was, suspect 1/3 doesn't matter, if you solve on calculator my answer you don't get yours error somewhere, check a see how I solved them, if you understand it you should be able to do pb 2
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