solving logarithmic and exponential equations

1. 8-3^x = -1
2. log(lowered 3)81=x
3. log x- log3=3

Question

solving logarithmic and exponential equations

1. 8-3^x = -1
2. log(lowered 3)81=x
3. log x- log3=3

kenljw · Answer

8-3^x = -1
3^x =9
x log(3) =9
x=9/log(3)

log x- log3=3
log(x) = 3 + log(3)
x = 10^(log(3)+3)
x= ]10^log(3)] 10^3
x=3 10^3

anonymous · Answer

are those the answers to 1 and 3?

kenljw · Answer

Does it look like the solutions

anonymous · Answer

Well I got 3 as the solution on number 1...  2.587 for number 7 and 300 for number 3?? are those right?

kenljw · Answer

I didn't do pb 2 because I didn't know what lowered 3 was, suspect 1/3
doesn't matter, if you solve on calculator my answer you don't get yours
error somewhere, check a see how I solved them, if you understand it you should be able to do pb 2

anonymous · Answer

THANK YOU SO MUCH!