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OpenStudy (anonymous):
factor:64x^3+125
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OpenStudy (anonymous):
(4x+5)*(16x^2-20x+25) if that helps :S
OpenStudy (anonymous):
Notice that 64x^3 is a perfect cube. That is, (4x)^3 = 64x^3. Also note that 125 is a perfect cube since it is 5^3. So to factor the sum of two cubes, you can either memorize the formula a^3 + b^3 = (a + b) (a^2 - ab + b^2) and substitute 4x for a and 5 for b in the formula or you can perform a long division knowing (4x + 5) must be one of the factors.
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