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OpenStudy (anonymous):
The two mumbers can be rolled to get a sum. Find p (sum is even
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OpenStudy (anonymous):
a sum of two number is even if either both number are even or both number are odd
OpenStudy (anonymous):
that may help
hartnn (hartnn):
sum can be either even or odd, so its a 50-50 chance..
OpenStudy (anonymous):
thats the nice way^^^
OpenStudy (anonymous):
The anwer choices are fractions
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hartnn (hartnn):
50-50 chance means 50% probability = 50/100 = 1/2
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