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Solve each equation by factoring: b^2 + 5b - 35 = 3b
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Firstly move 3b to the other side so you get the standard quadratic equation, which looks like Ax^2 + Bx + C = 0.
b^2 + 2b -35 = 0
once you do that then find 2 numbers that multyply to -35 and add up to (5-3)
yes now what mulitplies to -35 and adds up to 2?
Thanxs! haha(: give me a sec
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haha(: idk!
Thanx everyone! GBU!! Much appreciated! <3
-5*7=35 7-5
so b^2 + 2b -35 = 0 = (b-5)*(b+7) so solve (b-5)*(b+7)=0
Thank you so much!
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