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Mathematics 20 Online
OpenStudy (anonymous):

how to find height of this density curve ...

OpenStudy (anonymous):

OpenStudy (zarkon):

is it the inner rectangle from 1 to 3?

OpenStudy (anonymous):

yes

OpenStudy (zarkon):

then 1/2 is correct

OpenStudy (anonymous):

Thanks. It'll always be a fraction?

OpenStudy (anonymous):

1/ n?

OpenStudy (zarkon):

if it is a uniform distribution on [a,b] then the height is \(\frac{1}{b-a}\)

OpenStudy (zarkon):

\[\frac{1}{3-1}=\frac{1}{2}\]

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