Question

solve for C
a=1/3(a+b+c)

Answer 1

1. Multiply both sides by 3
2. Subtract a from both sides
3. Subtract b from both sides.

Answer 2

A.
c = 3A – (a – b)




B.

c = 3A – a – b




C.

c = 3a + 3b + A



D.

c = 3Aa

Answer 3

so 3a=(a+b+c)

Answer 4

Do you have A and a or are they both a ?

Answer 5

then...

Answer 6

I was wondering that.

Answer 7

3=(b+c)

Answer 8

then.. 3c?

Answer 9

idk about the a's

Answer 10

Look at the problem you were given. Does it have A in it?

Answer 11

yes, A=1/3(a+b+c)

Answer 12

Then:
1. Multiply both sides by 3
2. Subtract a from both sides
3. Subtract b from both sides.

Answer 13

1. 3A=1/3(a+b+c)
2. 3= 1(b+c)
3. b-3=c

Answer 14

1. You multiplied the left side by 3 but not the right side.

Answer 15

1. 3A=1/9(a+b+c)

Answer 16

What is:
\[3\times \frac{1}{3}=\]

Answer 17

1. 3A= 3/9(a+b+c)

Answer 18

\[3 \times \frac{1}{3}= \]

Answer 19

3/9

Answer 20

Would you please do that problem?

Answer 21

1

Answer 22

cross divide

Answer 23

3/1 x 1/3 = 1/1 x1/1

Answer 24

So what is:
\[3 \times \frac{1}{3}(a+b+c)=\]

Answer 25

1(a+b+c)

Answer 26

And what is 1(a+b+c)

Answer 27

a+b+c

Answer 28

Now proceed with the three steps of the problem I outlined above.

Answer 29

so then 3A=a+b+c
2. 3A=b+c
3. 3A=c

Answer 30

1. Multiply both sides by 3
2. Subtract a from both sides
3. Subtract b from both sides.

Answer 31

2. Subtract a FROM BOTH SIDES!!!!!!

Answer 32

2. 3= b+c
3. b-3=c

Answer 33

my answer isn't even close to one of the choices

Answer 34

A.
c = 3A – (a – b)




B.

c = 3A – a – b




C.

c = 3a + 3b + A



D.

c = 3Aa