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\[(a+b)(a-b)= a^2- b^2\]
a=4 and b= sqrt 8.
\[(4+\sqrt{8)}(4-\sqrt{8})\] The formula that "completeidiot" put is right if you say "4" is a and "sqt8" is b but the full way would be distributive property
By his solution the answer would be 4^2 - sqt8^2 (4+√8)(4-√8) You use FOIL First by First, [Outer by Outer + Inner by Inner], Last by Last. 4x4 + (4 x - sqt8 + sqt8 x -4) 4 x sqt 8
\[16-4\sqrt{8}+4\sqrt{8}+\sqrt{8^{2}}\] collect like terms: 4 sqt 8 cancel eachother out Now we're back to 16 - sq8^2
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