Chemistry
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OpenStudy (rane):
PLS IS THERE ANY KIND ENOUGH PERSON TO HELP ME?
PLS I NEED IN BALANCING THIS EQUATION!!!!!!!
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OpenStudy (rane):
KNO3 + Na2SO ====> K2SO4 + NaNO3
OpenStudy (rane):
can someone pls balance this, i tried bt i cant
OpenStudy (skullpatrol):
You need to "balance" the number of each element on both sides, right?
OpenStudy (rane):
yeah
OpenStudy (skullpatrol):
Try putting a 2 in front of the KNO3
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OpenStudy (rane):
i did
OpenStudy (skullpatrol):
Now you have the same number of K's on both sides, right?
OpenStudy (skullpatrol):
2KNO3 + Na2SO ====> K2SO4 + NaNO3
OpenStudy (rane):
yes
OpenStudy (rane):
now we have to put 2 infront of NaNO3 to balnace the nitrate
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OpenStudy (skullpatrol):
2KNO3 + Na2SO ====> K2SO4 + 2NaNO3
OpenStudy (rane):
now there has to be 2 placed in front of Na on the reactant side to balance it
OpenStudy (chmvijay):
no need its already there Na2 mean 2Na
OpenStudy (rane):
o yeah thanks
OpenStudy (chmvijay):
:)
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OpenStudy (rane):
i'm confused!
OpenStudy (skullpatrol):
Count up the number of EACH element on both sides to relieve your confusion :)
OpenStudy (rane):
no its not abt this equation
OpenStudy (rane):
wait so if i write net ionic equation then is it Na2 or SO4-2
OpenStudy (rane):
or just Na
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OpenStudy (skullpatrol):
Do the numbers match for this equation?
2KNO3 + Na2SO ====> K2SO4 + 2NaNO3
OpenStudy (rane):
yeah
OpenStudy (skullpatrol):
What about the O's?
OpenStudy (rane):
thank u ppls so much
OpenStudy (skullpatrol):
Thanks for trying to learn :)
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OpenStudy (rane):
so... who should i givw medal 2 becoz u both helped me out
OpenStudy (rane):
give*