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Chemistry 18 Online
OpenStudy (rane):

PLS IS THERE ANY KIND ENOUGH PERSON TO HELP ME? PLS I NEED IN BALANCING THIS EQUATION!!!!!!!

OpenStudy (rane):

KNO3 + Na2SO ====> K2SO4 + NaNO3

OpenStudy (rane):

can someone pls balance this, i tried bt i cant

OpenStudy (skullpatrol):

You need to "balance" the number of each element on both sides, right?

OpenStudy (rane):

yeah

OpenStudy (skullpatrol):

Try putting a 2 in front of the KNO3

OpenStudy (rane):

i did

OpenStudy (skullpatrol):

Now you have the same number of K's on both sides, right?

OpenStudy (skullpatrol):

2KNO3 + Na2SO ====> K2SO4 + NaNO3

OpenStudy (rane):

yes

OpenStudy (rane):

now we have to put 2 infront of NaNO3 to balnace the nitrate

OpenStudy (skullpatrol):

2KNO3 + Na2SO ====> K2SO4 + 2NaNO3

OpenStudy (rane):

now there has to be 2 placed in front of Na on the reactant side to balance it

OpenStudy (chmvijay):

no need its already there Na2 mean 2Na

OpenStudy (rane):

o yeah thanks

OpenStudy (chmvijay):

:)

OpenStudy (rane):

i'm confused!

OpenStudy (skullpatrol):

Count up the number of EACH element on both sides to relieve your confusion :)

OpenStudy (rane):

no its not abt this equation

OpenStudy (rane):

wait so if i write net ionic equation then is it Na2 or SO4-2

OpenStudy (rane):

or just Na

OpenStudy (skullpatrol):

Do the numbers match for this equation? 2KNO3 + Na2SO ====> K2SO4 + 2NaNO3

OpenStudy (rane):

yeah

OpenStudy (skullpatrol):

What about the O's?

OpenStudy (rane):

thank u ppls so much

OpenStudy (skullpatrol):

Thanks for trying to learn :)

OpenStudy (rane):

so... who should i givw medal 2 becoz u both helped me out

OpenStudy (rane):

give*

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