Question

Help needed please for exams
Find cot60 degrees-sin45degrees a)2-sqrt3/2
b.)2 square root3-3 square root 2/6
c)2-squareroot2/2
d)2 square root 2-3 square root 3/637

I got 1/ square root 3 -1/ square root 2 ...what is done next?

Answer 1

it would be better if you do not post this as an "exam" question :/

Answer 2

your values are fine, you might want to move up the sqrts tho; then its just subtracting fractions

Answer 3

its a practice past exam paper and i dont understand it.its not being graded

Answer 4

\[\frac{\sqrt3}{3}-\frac{\sqrt2}{2}\]

Answer 5

you prolly have forgotten, or dont remember how to move a radical

consider this:
\[\frac{1}{\sqrt a}\]
\[1*\frac{1}{\sqrt a}\]
\[\frac{\sqrt a}{\sqrt a}*\frac{1}{\sqrt a}\]
\[\frac{\sqrt a}{(\sqrt a)^2}\]
\[\frac{\sqrt a}{a}\]