Question

I tried doing this one on my own, but cant.
complete the square.
x^2+4x+3=0

Answer 1

what do the instructions say to do?

Answer 2

solve the equation by completing the square

Answer 3

Solve the equation by completing the square.
(1) x^2-4x+3=0 First, lets add -3 to both sides and we have:
x^2-4x=-3
Now why did we do that? If you look at the left side of the equation only, you will see that its actually a quadratic equation that's missing the "C" term. We are going to choose a new "C" for the left side of the equation and add it to both sides thereby creating a new quadratic equation on the left side that's a perfect square.
We'll take 1/2 of the "B" term(1/2)(4) or 2 and square it (2^2=4) and add this to both sides of the equation:
x^2-4x+4=-3+4 or
(x-2)^2=1 take sqrt of both sides
x-2=+or-sqrt(1) or
x-2=+or-1 now add 2 to both sidess
x=2+or-1
x=2+1=3 and
x=2-1=1



ck
substitute in (1)
3^2-4(3)+3=0
9-12+3=0
-3+3=0
0=0
1^2-4(1)+3=0
1-4+3=0
-3+3=0
0=0
Hope this helps.

Answer 4

well, looks like your problem is solved ^_^'

Answer 5

or you could do this.
4x^2-x-3=0


4(x^2-x/4-3/4)=0


4(x^2-x/4+1/16-1/16-3/4)=0


4((x-1/8)^2-1/64-3/4)=0


4((x-1/8)^2-49/64)=0


4(x-1/8)^2-4(49/64)=0


4(x-1/8)^2-49/16=0


4(x-1/8)^2=49/16


(x-1/8)^2=49/64


x-1/8 = sqrt(49/64) or x-1/8=-sqrt(49/64)


x-1/8 = 7/8 or x-1/8 = -7/8


x = 7/8+1/8 or x = -7/8+1/8


x = 8/8 or x = -6/8


x = 1 or x = -3/4


Answers are x=1 or x=−3 /4

Answer 6

Im starting to understand, but what would the answer be then?

Answer 7

Even though this is completing the square you could check your answers by factoring.
x^2+4x+3
(x-3)(x-1)
x=1, 3

Answer 8

oops

Answer 9

i told you either x=1 or -3/4

Answer 10

*(x+1)(x+3)
sorry about that

Answer 11

lol

Answer 12

can we do another one?

Answer 13

yea sure :)

Answer 14

x^2-10x+5=0

Answer 15

b=-10
a=1
c=-5

Answer 16

okay...