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Mathematics 16 Online
OpenStudy (anonymous):

Use complete sentences to explain how you would use graphing technology to find the solutions of 0 = 2x2 − 3x + 0.5. What do the solutions of 0 = 2x2 − 3x + 0.5 represent on the graph of the equation?

OpenStudy (anonymous):

do you mean 2x^2-3x+0.5

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

how would you graph this by hand?

OpenStudy (anonymous):

Im not quite too sure I'm having trouble with this part of algebra

OpenStudy (anonymous):

you would just plug in points right? for example, plug in x=2, then y= ?

OpenStudy (anonymous):

just like any other equation?

OpenStudy (anonymous):

exactly. a computer does the same thing, except it plugs in a whole lot of different points for you.

OpenStudy (anonymous):

Ok, but how would I use "Graphing Technology"

OpenStudy (anonymous):

well, what does it mean to get a solution to something like x^2+2x+1=0?

OpenStudy (anonymous):

To find the parabola?

OpenStudy (anonymous):

right. so when I use the quadratic equation to find the "solution" I'm asking where does this function equal zero

OpenStudy (anonymous):

in other words, at what point will this function cross the x-axis

OpenStudy (anonymous):

But what if it doesn't?

OpenStudy (anonymous):

good question! then you don't have any real solutions. For this problem, it looks like this: http://www.wolframalpha.com/input/?i=+2x^2+%E2%88%92+3x+%2B+0.5

OpenStudy (anonymous):

Ok that makes sense. But how would i solve to get where it does or doesn't cross?

OpenStudy (anonymous):

you have to use the quadratic equation. this is essentially what the "graphing technology" does to give you the solutions. It looks for the points on the x axis where y=0. so for a parabola you will sometimes have two points that look like this (a,0) and (b,0)

OpenStudy (anonymous):

So those points would mean where the parabola intercepts the x axis, and I don't need this "graphing technology" I can just solve it?

OpenStudy (anonymous):

Exactly, it is the intercepts. Sometimes it is easier to use a graphing technology though because it is very fast at plotting the points and doing the quadratic equation

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