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If cotx=5/7,the ^2 is equivalent to what? How do i find quivalent to? a.)12/7/5 c)5sqrt(74 d)sqrt74
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square both sides. if cot(x)=5/7, squaring both sides gives [cot(x)]^2=(5/7)^2.
or do you mean the square root?
the sqrt
makes more sense. do the same operation as I wrote earlier, just \[\sqrt{\cot(x)}=\sqrt{\frac{ 5 }{ 7}}\]
and rationalize.
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