Question

Trigonometry
cot squared x+cscx-4 is equivalent to
a.)csc squared x+csc x-5
b)csc squared 2x+cscx-3
c)cos^2x/sin^2 +1/cosx -4
d)-4

How is this question done?I need help

Answer 1

i believe it is C, because \[\cot x = \frac{ \cos x }{ \sin x }\] and \[\csc x = \frac{ 1 }{ \cos x }\]

Answer 2

Okk thanks but u i still dnt understand

Answer 3

actually that's wrong..

Answer 4

how is it suppose to be done?

Answer 5

substitute cot^2x with csc^2x-1

Answer 6

ok

Answer 7

ditto

Answer 8

ditto=same here;agreed?
ditto as in i agree with your answer choice as well

Answer 9

so, you do it