Question

Find the equation of the plane normal to r(t) = < e^t sin( (pi/2) t ) , e^t cos( (pi/2) t), t^2 > when t = 1

Answer 1

got to the point of having T'(1) = < e , -pi/2 , 2 > / sqrt( e^2 + pi^2/4 + 4) ) and r(1) = ( e, 0 , 1 )... just wondering how to write the plane equation