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OpenStudy (anonymous):
Find the absolute max and absolute min values of f on the given interval. f(x)= x^2-2x+2 [0,3]
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OpenStudy (anonymous):
compute \(f(0), f(3)\) and also the vertex at \(x=-\frac{b}{2a}=-\frac{-2}{2}=1\) biggest is max, smallest is min
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