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Which value of y is NOT part of the range of this function? f(x) = (9/x – 1) + 6
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are there choices?
Nope.
I believe the range is \[(-\inf,6)U(6,\inf)\] due to the fact that if y were to = 6 you would get a false value.
y = 9/(x-1) + 6 so (y-6)(x-1)=9 x=9/(y-6)1 thus y=6 is not defined
Thank you both
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np
bah that should say x=9/(y-6)+1
to find range find the inverse(assuming there is one) then find its domain
the domain of the inverse*
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