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Mathematics 19 Online
OpenStudy (dls):

Find the value of K such that the function is continuous

OpenStudy (dls):

\[\Huge f(x)=\frac{2^{x+2}-16}{4^x-16},if~ x \neq 2\] \[\Huge f(x)=k,if~x=2\]

Parth (parthkohli):

Isn't it \(1\)?

OpenStudy (dls):

\[\LARGE \lim_{x \rightarrow 2} \frac{2^{x+2}-16}{4^x-16}\] are we supposed to find this?

Parth (parthkohli):

Yes.

Parth (parthkohli):

It's clearly \(1\)/

Parth (parthkohli):

Or wait.

OpenStudy (dls):

\[\Large \frac{2^{x}.2^2\log2}{4^xlog4}\]

OpenStudy (dls):

something like that,maybe

Parth (parthkohli):

lol, I thought the question was something else. -_-

OpenStudy (dls):

im not sure what it means :/

OpenStudy (dls):

that gives log(-2) -.-

Parth (parthkohli):

Yeah, we have to find the limit.

OpenStudy (zzr0ck3r):

and left will equal right if a plug will fix...

OpenStudy (dls):

my limit comes out to be log(-2) which is undefined :/

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