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Mathematics
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Find the value of K such that the function is continuous
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\[\Huge f(x)=\frac{2^{x+2}-16}{4^x-16},if~ x \neq 2\] \[\Huge f(x)=k,if~x=2\]
Isn't it \(1\)?
\[\LARGE \lim_{x \rightarrow 2} \frac{2^{x+2}-16}{4^x-16}\] are we supposed to find this?
Yes.
It's clearly \(1\)/
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Or wait.
\[\Large \frac{2^{x}.2^2\log2}{4^xlog4}\]
something like that,maybe
lol, I thought the question was something else. -_-
im not sure what it means :/
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that gives log(-2) -.-
Yeah, we have to find the limit.
and left will equal right if a plug will fix...
my limit comes out to be log(-2) which is undefined :/
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