Question

Divide. (8x^2-20+15) / (2x-3)

Answer 1

use calculator

Answer 2

don't have one :(

Answer 3

mathway.com

Answer 4

8x^2-5/2x-3

Answer 5

I tried it just now it didn't give me an answer?

Answer 6

well the answer is 8x^2 -5 all over 2x-3
do you need an explanation?

Answer 7

is that just a-20 or should it be -20x...?

Answer 8

yes sorry it should be -20x

Answer 9

have you tried doing long division...?

Answer 10

for example, have a look at this:

Answer 11

We can say that :
\[8x^2-20x+3=(2x-3)(ax+b)+c\]
Now, trying to find a , b and c.
We have :
\[(2x-3)(ax+b)+c=2ax^2+2bx-3ax-3b+c=2ax^2+(2b-3a)x+(-3b+c)\]
So :
\[2a=8\\2b-3a=-20\\-3b+c=3\]
Then :
\[a=4\\b=-4\\c=-9\]

Answer 12

first it should be 20x and the
Quotient is (4x+4)
Remainder is 3