A capacitor of 2:0ÖF is connected to a battery of 2.0V through a resistance of 10kÊ. What is the initial current in the circuit and the current after 0.02s?
0:5ÖA and 0.074mA
7.4A and 5.0mA
0:2ÖA and 0.074mA
6:2ÖA and 7.04mA

Question

A capacitor of 2:0ÖF is connected to a battery of 2.0V through a resistance of 10kÊ. What is the initial current in the circuit and the current after 0.02s?
0:5ÖA and 0.074mA
7.4A and 5.0mA
0:2ÖA and 0.074mA
6:2ÖA and 7.04mA

anonymous · Answer

$$Q=EC(1-e ^{-t \div RC})$$
Q- charge on capacitor
E-emf of cell
C-capacitance
t-time
R-resistance.
Now differentiate the equation with respect to time and put value of 't' to get your answer.

anonymous · Answer

cant see the equation well sir

anonymous · Answer

http://hyperphysics.phy-astr.gsu.edu/hbase/electric/capchg.html This link may help.

anonymous · Answer

ok
thanks