Question

Show that the given function is a Probability Density Functions on the indicated interval. f(x) = 4x^3, [0, 1]

Answer 1

@cwrw238 can u help?

Answer 2

show that the integral from 0 to 1 = 1

Answer 3

how?

Answer 4

you know how to integrate ... or at least thats what alot of the postings youve had on here were about

Answer 5

\[\int_{0}^{1}4x^2~dx\]

Answer 6

*4x^3 dx that is

Answer 7

yes i do know and okay

Answer 8

i probability density function can be defined as: the area under the curve is equal to 1

to find the area under a curve, we integrate. if the integration on that interval is equal to 1, then we fit the definition of a PDF