Question

someone HELP ME: write the expression as a complex number in standard form.
(-1+5i)(6+3i)

Answer 1

-1*6+(-3i)+30i+15&i^2
-6+27i-15
27i-21

Answer 2

Here you are multiplying complex numbers.
You start out by multiplying with FOIL.
(-1 + 5i)(6 + 3i) =
= -1 * 6 + (-1) * (3i) + 5i * 6 + 5i * (3i)
Now you do the multiplications:
= -6 - 3i + 30i + 15i^2
Now you simplify i^2, since i^2 = -1
= -6 - 3i + 30i + 15(-1)
Multiply 15 by -1
= -6 - 3i + 30i - 15
Now you combine like terms like we did before.
= -6 - 15 - 3i + 30i
= -21 + 27i
This is standard form for a complex number

Answer 3

same thing as(a+b)(c+d) but i^2=-1

Answer 4

write the expression as a complex number
dividing complex numbers