Question

The point (2, 3) is a critical point of gt(u,v)=(u-3)^2 + (v-2)^2. this is wrong, right? because it has to be (3,2)?

Answer 1

Couldn't have said it better! Medal please? :D

Answer 2

no, you set the derivative to 0, not the function..

Answer 3

ahh I c the derivative does not change it:0

Answer 4

so it should be 3,2 for u=3 and v=2?