Can someone please help me?
dividing powers
4. x^2y^9 divided by 2x^3y^6

5. a^3b^2c divided by a^3bc^5

6. 3pq^3 divided by 4p^4q^8r

Question

Can someone please help me?
dividing powers
4. x^2y^9 divided by 2x^3y^6

5. a^3b^2c divided by a^3bc^5

6. 3pq^3 divided by 4p^4q^8r

zzr0ck3r · Answer

(x^2y^9)/(2x^3y^6)
= x^(2-3)*y^(9-6)/2

zzr0ck3r · Answer

= y^3/(2x)

anonymous · Answer

can you do 5 & 6 please and thank you?

zzr0ck3r · Answer

all you need on all these is the fact that a^b/a^c = a^(b-c) = 1/a^(c-b)

zzr0ck3r · Answer

we are not here to do them for you, I showed you what I did, you attempt it and show me what your doing

anonymous · Answer

i know but i only have a few days to understand this and to get all of them done /: im stuck

anonymous · Answer

i'm still stuck on 5 & 6

rajee_sam · Answer

In all these types of problems you have to combine exponents with same base