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MIT 18.06 Linear Algebra, Spring 2010
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Is the solution to problem 4.2 in the check yourself section correct. Instead of all 1's in the lower diagonal it seems that it should be all -1's in the lower diagonal. Thanks, Nate
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Hi Nate, The elimination matrices do contain the number -1. However, we are using the inverse of the elimination matrices to find the matrix U, hence the number 1 would appear instead of -1. If you multiply L and U you'll find that it indeed produces A.
You're correct and I see my mistake. Thank you.
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