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Mathematics 8 Online
OpenStudy (anonymous):

The length of the hypotenuse of a 30-60-90 triangle is 10. find the perimeter.

OpenStudy (agent0smith):

Sides of a 30-60-90 triangle look like this: |dw:1370641538536:dw|

OpenStudy (agent0smith):

You know the hypotenuse is 10, so you have: |dw:1370641627857:dw| You need to find the other two sides (by finding x) and then add all three sides for perimeter.

OpenStudy (anonymous):

Ok so does that mean for x^2(3) I would do 10^2(3)? which would be 300?

OpenStudy (agent0smith):

There is no x^2(3). It's \[\large x \sqrt3\] on the left.

OpenStudy (agent0smith):

And 2x = 10 so from that you can find x.

OpenStudy (anonymous):

x=5 right

OpenStudy (agent0smith):

Yes, now you can find the other two sides.

OpenStudy (anonymous):

okay thank you

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