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6m – 2 = 10 – 6(2 – m)
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Do you want to solve the equation ?
yes do I distribute 1st
Yes, and then ? tell us what you get !
6m-2=10-12m-6m
NO ! There is an error with the last sign It is (+6m) not (-6m) because you have \[-6\times(-m)\]
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o
So, when you distribute the brackets you get : \[6m – 2 = 10 -12 +6m\]
ok
is it m=4
You observe that 6m is in the two sides of the equality, so we delete it ! It remains : \[-2=10-12\] which is true ! So, The set of solution is the set of all real numbers !
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ok
-2=-2
Yes, you get -2=-2, this means that the equation is always true for all value of m So : The set of solution is the set of all real numbers ! In other words! : \[S=\mathbb R\]
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