Question

HELP? ALGEBRA!

Answer 1

anyone please help?

Answer 2

OK ! Wait a minute !

Answer 3

okay!

Answer 4

\[\frac{(a-4)(a+3)}{a^2-a}\div\frac{2(a-4)}{(a+3)(a-1)}\\=\frac{(a-4)(a+3)}{a(a-1)}\times\frac{(a+3)(a-1)}{2(a-4)}\\=\frac{(a+3)^2}{2a}\]

Answer 5

thank you!

Answer 6

can anyone help me with this?

Answer 7

For factoring
\[x^2+5x-6\]
we should find two numbers a and b such that ab=-6 and a+b=5
We can take :
\[a=6~~~b=-1\]
So :
\[x^2+5x-6=(x+a)(x+b)=(x+6)(x-1)\]

Answer 8

oh okay

Answer 9

wait idk which one it is?