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What is the value of b^2 - 4ac for the following equation? 2x^2 + 3x = -1
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Choices; 0 1 17
???
ax^2+bx+c
ax^2+bx+c=0
2x2 + 3x +1=ax^2+bx+c a=2 b=3 c=1
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So then what's the value for b^2 - 4ac ?
Apparently the right answer is 1. But what's the solution to that?
@cinar
its 1. b is 3 a is 2 and c is 1. so \[3^2-4(2)(1)\]
then you get 9-8 which is 1
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Ah. Makes sense. Thank you!!! :)
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