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Mathematics 13 Online
OpenStudy (anonymous):

what is the product of -3x^2y and (5xy^2+xy)

OpenStudy (anonymous):

-15x^(2y+1)*y^3-3x^(2y+1)*y^2

OpenStudy (anonymous):

the above answer is correct

OpenStudy (anonymous):

which one

OpenStudy (anonymous):

Lemme take a crack at this. Are you there?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Okay, so the original problem is: -3x^2y * 5xy^2+xy This can be broken down into 2 parts: -3x^2y * 5xy^2 and -3x^2y * xy Do you see what I did?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Okay. So let's take each part in turn. Can you multiply these together? -3x^2y * 5xy^2

OpenStudy (anonymous):

-15x^2x^2y^2

OpenStudy (anonymous):

are anyone here

OpenStudy (anonymous):

Ummm...not exactly... :-) On a problem like this, you have to multiply each part like itself. IOW, you multiply the coefficients first (that's the number part) Then you multiply the X-thingies Then you multiply the Y-thingies. So for this one, you would have: -3 * 5 Then you'd have x^2 * x (or x * x^2) And then you'd have y * y^2 (or y^2 * y) can you solve each of them?

OpenStudy (anonymous):

-15x x^3 y^4

OpenStudy (anonymous):

is it correct

OpenStudy (anonymous):

-5 * 3 isn't -15x There's no "x" in "-3" or "5" x^3 is correct!!! :-) y^4 is wrong.

OpenStudy (anonymous):

I just guess , it was first one

OpenStudy (anonymous):

You don't learn anything by guessing. But if you're tired, I can go away.

OpenStudy (anonymous):

It is simple. Pretty much, anyway... :-) But you have to learn it first. Everything is hard before you understand it.

OpenStudy (anonymous):

Yes, I knew it was the first one before I even started here. :-) I was trying to teach you how to figure it out like I did.

OpenStudy (anonymous):

I'm not going to bang you on the head about it. Just post another problem if you want to learn how to solve it, and if I can help, then I will. I'll go away now. :-)

OpenStudy (anonymous):

thank you

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