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Use the law of cosines to find the value of 2*2*2 cos(θ)
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@Jhannybean
Well, do you know the formula for the Law of Cosines?
$$c^2=a^2+b^2-2ab\cos C$$In our case, \(c=1\) and \(a=b=2\). Our \(C\) here is \(\theta\).$$1^2=2^2+2^2-2(2)(2)\cos\theta\\1=8-8\cos\theta\\-8\cos\theta=-7\\8\cos\theta=7$$
So, I made a mistake when I got -8.. Thank you very much
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