Question

find the value of c such that one solution to 4x^2-6x+c=0 is x=3.

Answer 1

\[4x^{2}-6x+c=0\]\[4(3)^{2}-6(3)+c=0\]\[4(9)-6(3)+c=0\]\[36-18+c=0\]You finish it from there.

Answer 2

36-18+c=0
-18+c=0
+18 +18
c=18 from here idk what else to do

Answer 3

\[36-18+c=0\]\[18+c=0\]\[c=-18\]

Answer 4

oh yeah idk what i was thinking

Answer 5

is that it ?

Answer 6

Yes