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Help Please! For some reason I can't get the second question right =/
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is the second derivative \[-2\sin(x)-\sqrt{2}\]?
then you would need to solve \[-2\sin(x)-\sqrt2=0\] \[\sin(x)=-\frac{\sqrt{2}}{2}\]
show us what u got for your 2nd derivative we tell u if its right
you have one solution \(\frac{5\pi}{4}\) as you said other one is across at \(\frac{7\pi}{4}\)
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|dw:1370746615871:dw|
yeah I'm not allowed a calculator so I'm having difficulties - can you show me your calculations if you can?
and i got -2sin(x)-sqrt(2) for second derivative
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