Question

Write the standard equation of the circle center (-6,-8), that passes through (0,0)

Answer 1

standard equation:

\[(x - h)^2 + (y - k)^2 = r^2\]

where (h, k) is the circle's center and r is the circle's radius.

the radius must be the distance between (-6. -8) and (0, 0), which can be found using the distance formula.

\[r = d = \sqrt{ (x_2 - x_1)^2 + (y_2 - y_1)^2 }\]