During a baseball game, a batter hits a high
pop-up. If the ball remains in the air for 6.82 s, how
high does it rise? The acceleration of gravity
is 9.8 m/s^2.

Question

During a baseball game, a batter hits a high
pop-up. If the ball remains in the air for 6.82 s, how
high does it rise? The acceleration of gravity
is 9.8 m/s^2.

anonymous · Answer

I used V = V(initial) - gt to find the initial velocity,
0 = vi -9.8(3.41), because I did half of 6.82 because I want it at it's max point and got 33.418 for the initial velocity.
Then I plugged it into d=vi(t)-1/2(g)t^2
33.418(3.41)-1/2(9/8)(3.41)... and I just figured out what I did wrong nevermind guys~