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OpenStudy (anonymous):
In Triangle ABC, Angle B=90*, SinC=3/5. AB=9cm. Find BC.
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jhonyy9 (jhonyy9):
can you drawing it ? this will help you sure
OpenStudy (anonymous):
@jhonyy9 - I have it on my paper...... should i draw it here?
jhonyy9 (jhonyy9):
yes please
jhonyy9 (jhonyy9):
just for i can explaning to you for you can understanding it easy
OpenStudy (anonymous):
|dw:1370789127024:dw| Okay? @jhonyy9
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jhonyy9 (jhonyy9):
can you writing here what mean sinC ,sinus of angle C , using proportionality of sides ?
OpenStudy (anonymous):
SinC=AB/BC?
jhonyy9 (jhonyy9):
exactly
so than now just you need rewriting it and let be equale by 3/5
and from this you njust need calculi BC
ok ?
jhonyy9 (jhonyy9):
???
OpenStudy (anonymous):
Given AB is 9cm but now AB will be 3 ! Thats wer i am confused
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jhonyy9 (jhonyy9):
so
let be BC = x
3/5 = 9/x so than cros multiplie
3x=45 divide both sides by 3
x= 15
right ?
OpenStudy (anonymous):
Ya!
jhonyy9 (jhonyy9):
yw
good luck
OpenStudy (anonymous):
Thanks!! x= 15cm right?
jhonyy9 (jhonyy9):
yes
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OpenStudy (anonymous):
Thanks a lot! @jhonyy9 !!
jhonyy9 (jhonyy9):
yw
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