Question

Can someone please help me with this?
-Attachment

Answer 1

In waveform P there are four crests and so there are four waves ok? (for the motion from 0 to 18)
In waveform Q there four crest and and one trough that makes 4.5 waves
for waveform P.

no of waves time period
4 in 18s
it is directly proportional we get x =4/18=0.2222222hz this is f1(as frequency is the number of waves in one second)
now lets find T1
T1=1/f =1/0.222222=4.5s
This is for waveform P

now for waveform Q
no of waves time period
4.5 in 18s
x=4.5/18
x=0.25
T2= 1/0.25
T2=4s

Step 2. (More of practical work and drawing using the T1 and T2)
now to find the phase difference draw two vertical lines from one wave form to the other remember it should be perpendicular to the x axis
4s means one wave of waveform Q
4.5 means one wave of waveformP
9s means two waves of waveform Q draw the lines and see what u get
at 4 s u will see 0 phase difference
at 4.5 s there is a difference of 1/8 of a wave
at 9 s there is a difference of 1/4 of wave

Peace x

Answer 2

I didn't understand step 2. O.o

Answer 3

Calibrate your two diagrams using an appropriate scale. The total is= 18s Okay? So half diagram would be 9s for both
Draw a straight line from diagram 1 starting from a crest or trough wherever you have adjusted the point (9s) vertically downwards diagram two.
You will see the phase difference
Repeat this step from time 4s and 4.5s

Answer 4

Oh, okay. Thank you so much! :)