81x2-1
do u want to factor this?
you would have to be able to identify this as difference of two squares... you would have to know that for difference of two squares, \[\large a^2-b^2=(a+b)(a-b)\]
if we rewrite the question, \[\large (81x^2-1^2)\] what is our a? what is our b?
Simplifying 81x2 + -1 = 0 Reorder the terms: -1 + 81x2 = 0 Solving -1 + 81x2 = 0 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + 81x2 = 0 + 1 Combine like terms: -1 + 1 = 0 0 + 81x2 = 0 + 1 81x2 = 0 + 1 Combine like terms: 0 + 1 = 1 81x2 = 1 Divide each side by '81'. x2 = 0.01234567901 Simplifying x2 = 0.01234567901 Take the square root of each side: x = {-0.111111111, 0.111111111}
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