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Solve 3the square root of x minus three) – 5 = 16 x = 5 x = 19 x = 52 x = 67
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sqrt(x - 3) - 5 = 16 sqrt(x - 3) = 21 now square both sides
how did you get rid of the cubed root? \[\sqrt[3]{x-3} - 5 = 16\]
oh - missed the 3 sorry
r u sure thats right not 3 times the square root of x - 3?
it probably is three times the square root, im sorry
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so squared it would be 3(x-3) = 441?
lol ok so 3 sqrt(x - 3) = 21 sqt(x - 3) = 21/3 = 7 x- 3 = 49
so x= 52?
yep
cool, thank you!!
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yw
the aim is to isolate the square root bit then square both sides
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