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Simplify (x – 4)(x2 + 3x + 2) x3 – x2 + 14x – 8 x3 + 7x2 – 10x – 8 x3 – x2 – 10x – 8 x3 + 7x2 + 14x – 8
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\[\large (x-4)(x^2+3x+2)\] multiply by foiling (i think that's what it's called)\[\large \color{green}x(x^2+3x+2)-\color{green}4(x^2+3x+2)\] multiply the "x" and the "4 into (x^3 +3x +2)\[\large x^3+3x^2+2x - 4x^2-12x -8\] rearrange your terms so that they're easier to evaluate. \[\large x^3 -4x^2 + 3x^2 -12x+2x -8\]\[\large x^3-x^2-10x-8\]
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