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Mathematics 11 Online
OpenStudy (anonymous):

given:... find(f+g)(X)

OpenStudy (anonymous):

OpenStudy (anonymous):

find (f+g)(x)

OpenStudy (anonymous):

add

OpenStudy (anonymous):

i.e. put a plus sign between them

OpenStudy (anonymous):

In general : \[(f+g)(x)=f(x)+g(x)\\ \\(\lambda f)(x)=\lambda f(x) \\(fg)(x)=f(x)g(x) \\\left(\frac fg\right)(x)=\frac{f(x)}{g(x)}~~ g(x)\ne 0 \]

OpenStudy (anonymous):

im still really confused

OpenStudy (anonymous):

\[(f+g)(x)=f(x)+g(x)=\frac{3}{x+6}+x^2-3=\frac{3+(x^2-3)(x+6)}{x+6}=\frac{3+x^3+6x^2-3x-18}{x+6}\\=\frac{x^3+6x^2-3x-15}{x+6}\]

OpenStudy (anonymous):

thank you that helps a lot

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