Question

Partial fractions help?

Answer 1

\[\frac{ x^2+8x-3 }{ x^3+3x^2 }\]

Answer 2

Just help me split that up?

Answer 3

Because I feel like I am doing something wrong.

Answer 4

sorry, its been a while since ive done partial fractions so hopefully i dont get this wrong


\[x^3+3x^2 = x^2 (x+3)\]

Answer 5

\[\frac{x^2+8x-3}{x^3+3x^2} = \frac{x^2+8x-3}{x^2(x+3)} = \frac{A}{x+3} + \frac{ Bx +C}{x^2}\]

Answer 6

It's okay. I got it :) .