Question

What is the solution to the system of equations?
2x-3y-2z=-7
x-3y-3z=4
x-2y-z=-3

Answer 1

x=2y+z-3
so
(2y+z-3)-3y-3z=4
-y-2z-3=4
so y = -7-2z
so
x = 2(-7-2z)+z-3
so
2x-3y-2z=-7 ==>2(2(-7-2z)+z-3)-3(-7-2z)-2z=-7
-28-8z+z-3+21+6z-2z=-7
-8z+z+6z=3
z=-3
y = -1
x = -8

Answer 2

make sense @DribleDaVaca19 ?