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Mathematics 17 Online
OpenStudy (anonymous):

Line AB is tangent to . If AO = 48 and BC = 100, what is AB? The diagram is not drawn to scale. PLEASE HELP :(

OpenStudy (anonymous):

OpenStudy (anonymous):

Can you help me please?

OpenStudy (anonymous):

@FutureMathProfessor

OpenStudy (mayankdevnani):

@Dwreck AO=Radius and CO is also radius. so AO=CO=radius and AO=48 units So, CO=48 units

OpenStudy (mayankdevnani):

ok... got it @Dwreck

OpenStudy (anonymous):

THank you so much!

OpenStudy (mayankdevnani):

what is the value of BC???

OpenStudy (mayankdevnani):

@Dwreck

OpenStudy (anonymous):

Oh wait, do I add them up?

OpenStudy (mayankdevnani):

yeah!! please

OpenStudy (anonymous):

96

OpenStudy (mayankdevnani):

you are wrong!!! BC+CO=????

OpenStudy (mayankdevnani):

@Dwreck

OpenStudy (anonymous):

Umm

OpenStudy (mayankdevnani):

can you add them up(BC+CO)???

OpenStudy (anonymous):

148??

OpenStudy (mayankdevnani):

correct

OpenStudy (anonymous):

YES

OpenStudy (mayankdevnani):

then BO=148 unit

OpenStudy (mayankdevnani):

correct

OpenStudy (anonymous):

That's the answer?!

OpenStudy (mayankdevnani):

no

OpenStudy (anonymous):

Oh..

OpenStudy (mayankdevnani):

by using phythagoreas theorem, \[\huge AB^2+AO^2=BO^2\] \[\huge AB^2+48^2=148^2\] \[\huge AB^2=148^2-48^2\] can you solve it??? @Dwreck

OpenStudy (anonymous):

140?!?!?!

OpenStudy (anonymous):

I have another question if that's okay...

OpenStudy (mayankdevnani):

you are correct!! @Dwreck

OpenStudy (mayankdevnani):

@Dwreck please ask!! If i can help, its great

OpenStudy (anonymous):

Find x. The figure is not drawn to scale.

OpenStudy (mayankdevnani):

can you write full question???

OpenStudy (anonymous):

A. 106° B. 26.5° C. 53° D. 37°

OpenStudy (mayankdevnani):

@Dwreck can you write the whole problem statement???

OpenStudy (anonymous):

That's all it shows :/

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