Mathematics
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OpenStudy (anonymous):
Line AB is tangent to . If AO = 48 and BC = 100, what is AB?
The diagram is not drawn to scale. PLEASE HELP :(
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OpenStudy (anonymous):
OpenStudy (anonymous):
Can you help me please?
OpenStudy (anonymous):
@FutureMathProfessor
OpenStudy (mayankdevnani):
@Dwreck AO=Radius and CO is also radius.
so AO=CO=radius
and AO=48 units
So, CO=48 units
OpenStudy (mayankdevnani):
ok... got it @Dwreck
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OpenStudy (anonymous):
THank you so much!
OpenStudy (mayankdevnani):
what is the value of BC???
OpenStudy (mayankdevnani):
@Dwreck
OpenStudy (anonymous):
Oh wait, do I add them up?
OpenStudy (mayankdevnani):
yeah!! please
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OpenStudy (anonymous):
96
OpenStudy (mayankdevnani):
you are wrong!!!
BC+CO=????
OpenStudy (mayankdevnani):
@Dwreck
OpenStudy (anonymous):
Umm
OpenStudy (mayankdevnani):
can you add them up(BC+CO)???
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OpenStudy (anonymous):
148??
OpenStudy (mayankdevnani):
correct
OpenStudy (anonymous):
YES
OpenStudy (mayankdevnani):
then BO=148 unit
OpenStudy (mayankdevnani):
correct
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OpenStudy (anonymous):
That's the answer?!
OpenStudy (mayankdevnani):
no
OpenStudy (anonymous):
Oh..
OpenStudy (mayankdevnani):
by using phythagoreas theorem,
\[\huge AB^2+AO^2=BO^2\]
\[\huge AB^2+48^2=148^2\]
\[\huge AB^2=148^2-48^2\]
can you solve it??? @Dwreck
OpenStudy (anonymous):
140?!?!?!
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OpenStudy (anonymous):
I have another question if that's okay...
OpenStudy (mayankdevnani):
you are correct!! @Dwreck
OpenStudy (mayankdevnani):
@Dwreck please ask!! If i can help, its great
OpenStudy (anonymous):
Find x. The figure is not drawn to scale.
OpenStudy (mayankdevnani):
can you write full question???
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OpenStudy (anonymous):
A. 106°
B. 26.5°
C. 53°
D. 37°
OpenStudy (mayankdevnani):
@Dwreck can you write the whole problem statement???
OpenStudy (anonymous):
That's all it shows :/