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Algebra
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I will now use algebraic equations to solve different math problems using the integers in step two from the birthday date. a^3-b^3 〖10〗^3-(-31)^3 1000—29791 1000+29791 30,791 The variables a and b are both have an exponents of 3. I plugged in the integer 10 for the variable a and plugged the integer -31 for the variable b. Both integers were raised to the given exponents, which was 3. Minus a negative it becomes a plus. Here is the answer. (a-b)(a^2+ab+b^2 ) [10-(-31) ][〖10〗^2+10(-31)+(-31)^2 [10+31][100+(-310)+62] 41(100-310+62) 41(149)
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