Question

I will now use algebraic equations to solve different math problems using the integers in step two from the birthday date.
a^3-b^3
〖10〗^3-(-31)^3




1000—29791


1000+29791


30,791 The variables a and b are both have an exponents of 3. I plugged in the integer 10 for the variable a and plugged the integer -31 for the variable b.

Both integers were raised to the given exponents, which was 3.

Minus a negative it becomes a plus.


Here is the answer.

(a-b)(a^2+ab+b^2 )
[10-(-31) ][〖10〗^2+10(-31)+(-31)^2


[10+31][100+(-310)+62]



41(100-310+62)

41(149)